N=PV/RT
(1.00 ATM)(.800 L)/(0.0821 (L)(atm)/(mol)(K)(292K) =
0.3333 mol CO2

(0.03 mol CO2)(1mol NaHCO3)(84g NaHCO3)/(1mol CO2)(1mol NaHCO3).
= 2.52 gNaHCO3

(0.03 mol CO2)(1 mol CH3 COOH)(60g CH3COOH)(100 vinegar)/(1 mol)(1mol CH3 COOH)(5 gCH3COOH) = 36 mL vinegar

Calculations