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Lecture 2, Answer 2
a. K(g)-> K (g)+e
b. According to Coulomb’s Law, F=k q1q2/d2, the force of attraction between two charged particles decreases as the distance between them increases, as distance is the denominator of the equation. Because the outermost electron is very far from the nucleus, the force is very low.
c. The electron in the n=4 shell is partially ‘shielded’ from the force of attraction by the inner core electrons from the n=1, n=2, and n=3 shells. The electron in n=4 is repelled by the negative charges of those inner core electrons, and this reduces the force of attraction between it and the positive nucleus.
+ –
Chris
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