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18. So what does that have to do with the BBS-ISL Matrix?

Every PT resides uniquely on a row upon the matrix, and, the Pythagorean Theorem Proof of any, and all, such PTs is found by sliding the “squares” of the PT’s sides to the origins of the matrix.

19. Does every row have a PT?

No. Only those rows with Squared numbers from the PD above.

20. Explain?

Take a PD number from anywhere on the PD (9 +). Drop down that column until you intersect with a row cell value that is also a Squared PD number. Next, go along that same row until you reach a 2nd Squared PD number. Those two “squared” cell values = b and a , and, the c value will be at the end of that row on the PD. That is the c = a + b PT. Squared Pair-Sets.

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2

2

2

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